Morphocompletion for #1712 ⟨a, b | aabbaaaba=b

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. babbaaaba ⇒ aabbaaabb
2. aabbaaaba ⇒ b
3. bbbaaabaaaaba ⇒ aabbaaaaabbab
4. babbaaaaabbaaabb ⇒ aabbaaabbbbaaaba
5. aabbaaaaabbaaabb ⇒ bbbaaaba
6. bbbaaabaaaaaabbaaabb ⇒ aabbaaaaabbabbbaaaba
7. babbaaaaabbaaaaabbaaaaabbab ⇒ aabbaaabbbbaaababaaabaaaaba
8. aabbaaaaabbaaaaabbaaaaabbab ⇒ bbbaaababaaabaaaaba
9. bbbaaabaaaaaabbaaaaabbaaaaabbab ⇒ aabbaaaaabbabbbaaababaaabaaaaba
10. bbbaaababaaabaaaababaaabaaaaba ⇒ aabbaaaaabbaaaaabbaaaaabaabbab
11. babbaaaaabbaaaaabbaaaaabaabbaaabb ⇒ aabbaaabbbbaaababaaabaaaababaaaba
12. aabbaaaaabbaaaaabbaaaaabaabbaaabb ⇒ bbbaaababaaabaaaababaaaba
13. bbbaaabaaaaaabbaaaaabbaaaaabaabbaaabb ⇒ aabbaaaaabbabbbaaababaaabaaaababaaaba
14. bbbaaababaaabaaaababaaabaaaaaabbaaabb ⇒ aabbaaaaabbaaaaabbaaaaabaabbabbbaaaba
15. aabbaaaaabbaaaaabbaaaaabaabbaaaaabbaaaaabbab ⇒ bbbaaababaaabaaaababaaababaaabaaaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] baa, [3/3] abb, [3/4] bba, [3/5] aba, [3/6] bab
Length 4:[4/0] aaaa, [4/1] aabb, [4/2] baaa, [4/3] aaab, [4/4] bbaa, [4/5] abba, [4/6] aaba
Length 5:[5/0] bbaaa, [5/1] aabba, [5/2] aaabb, [5/3] abbaa, [5/4] aaaaa, [5/5] baaaa, [5/6] aaaab
Length 6:[6/0] aabbaa, [6/1] abbaaa, [6/2] baaaaa, [6/3] aaaaab, [6/4] bbaaaa, [6/5] aaabba, [6/6] aaaabb
Length 7:[7/0] aabbaaa, [7/1] bbaaaaa, [7/2] baaaaab, [7/3] abbaaaa, [7/4] aaaabba, [7/5] aaaaabb, [7/6] aaabbaa

Considering [length 2 / frequency 0] aa=c.

Step 2

Rewriting system is complete. See a, b | aabbaaaba=b.