Morphocompletion for #1709 ⟨a, b | aabbaaaab=a⟩

Back:⟨a, b | aabbaaaab=a⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaaab ⇒ aabbaaa
2. aaaaababb ⇒ a
3. aabbaaaa ⇒ aaaaabab
4. aaaaababababb ⇒ aabba
5. aaaaabababba ⇒ aaaaabaababb
6. aaaaababaababb ⇒ aabbaa
7. aaaaabbbaaaa ⇒ aaaaabaaabab
8. aaaaabaaababba ⇒ aaaaab
9. aaaaababaaabab ⇒ abaaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] bab, [3/4] abb, [3/5] baa, [3/6] bba
Length 4:[4/0] aaaa, [4/1] abab, [4/2] aaab, [4/3] aaba, [4/4] babb, [4/5] baaa, [4/6] abaa
Length 5:[5/0] aaaaa, [5/1] aaaab, [5/2] aabab, [5/3] aaaba, [5/4] ababb, [5/5] baaaa, [5/6] ababa
Length 6:[6/0] aaaaab, [6/1] aaabab, [6/2] aaaaba, [6/3] aababb, [6/4] bbaaaa, [6/5] aababa, [6/6] ababba
Length 7:[7/0] aaaaaba, [7/1] aaaabab, [7/2] aaababa, [7/3] baaabab, [7/4] aaababb, [7/5] abababb, [7/6] abbaaaa

Considering [length 4 / frequency 0] aaaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaaaab=a⟩.