Morphocompletion for #1693 ⟨a, b | aabababaa=a

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaba ⇒ abaaa
2. aabababa ⇒ abababaa
3. abababaaa ⇒ a
4. abababaabaaa ⇒ aaba
5. abababaababaaa ⇒ aababa
6. abababaabaabaaa ⇒ aabaaba
7. abababaababaabaaa ⇒ aababaaba
8. abababaabaababaaa ⇒ aabaababa
9. abababaabaabaabaaa ⇒ aabaabaaba
10. abababaababaababaaa ⇒ aababaababa
11. abababaababaabaabaaa ⇒ aababaabaaba
12. abababaabaababaabaaa ⇒ aabaababaaba
13. abababaabaabaababaaa ⇒ aabaabaababa
14. abababaabaabaabaabaaa ⇒ aabaabaabaaba
15. abababaababaababaabaaa ⇒ aababaababaaba
16. abababaababaabaababaaa ⇒ aababaabaababa
17. abababaabaababaababaaa ⇒ aabaababaababa
18. abababaababaabaabaabaaa ⇒ aababaabaabaaba
19. abababaabaababaabaabaaa ⇒ aabaababaabaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa
Length 3:[3/0] aba, [3/1] baa, [3/2] bab, [3/3] aab, [3/4] aaa
Length 4:[4/0] abab, [4/1] abaa, [4/2] baba, [4/3] aaba, [4/4] baab, [4/5] baaa, [4/6] aaab
Length 5:[5/0] ababa, [5/1] abaab, [5/2] baaba, [5/3] abaaa, [5/4] babaa, [5/5] aabaa, [5/6] aabab
Length 6:[6/0] abaaba, [6/1] ababab, [6/2] ababaa, [6/3] baabaa, [6/4] babaab, [6/5] aabaaa, [6/6] bababa
Length 7:[7/0] abababa, [7/1] abaabaa, [7/2] ababaab, [7/3] babaaba, [7/4] baabaaa, [7/5] aabaaba, [7/6] baabaab

Considering [length 5 / frequency 0] ababa=c.

Step 2

Rewriting system is complete. See a, b | aabababaa=a.