Morphocompletion for #1615 ⟨a, b | aaabaabaa=a⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaba ⇒ abaaa
2. aabaaba ⇒ abaabaa
3. aababaaba ⇒ abaababaa
4. abaabaaaa ⇒ a
5. aababaabaa ⇒ abaababaaa
6. aabababaaba ⇒ abaabababaa
7. aabababaabaa ⇒ abaabababaaa
8. aababababaaba ⇒ abaababababaa
9. abaababaaaaa ⇒ aaba
10. aababababaabaa ⇒ abaababababaaa
11. abaabababaaaaa ⇒ aababa
12. aabababababaabaa ⇒ abaabababababaaa
13. abaababababaaaaa ⇒ aabababa
14. abaabababababaaaaa ⇒ aababababa
15. abaababababababaaaaa ⇒ aabababababa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa70lf:51,lp:9,ls:10,rf:27,rp:5,rs:9,lsrp:5,lprs:9,lsrs:4,a:2
[2/1]ab66lf:60,lp:6,rf:48,rp:9,a:2
[2/2]ba65lf:60,ls:5,rf:48,rs:5,a:2
[3/0]aba71lf:60,lp:6,ls:5,rf:48,rp:9,rs:5,lsrp:5,lprs:5,a:2
[3/1]aab31lf:23,lp:8,rf:13,rp:5,a:2
[3/2]bab31lf:31,rf:26,a:10
[3/3]baa28lf:24,ls:4,rf:17,rs:4,a:2
[3/4]aaa25lf:18,lp:1,ls:6,rf:5,rs:5,lprs:1,a:2
[4/0]aaba36lf:23,lp:8,ls:5,rf:13,rp:5,rs:1,re:1,a:2
[4/1]abaa34lf:24,lp:6,ls:4,rf:17,rp:9,rs:4,lsrp:4,a:2
[4/2]abab31lf:31,rf:26,a:10
[4/3]baba31lf:31,rf:26,rs:4,a:10
[4/4]aaaa17lf:11,ls:6,a:2
[4/5]baab14lf:14,rf:8,a:2
[4/6]baaa6lf:6,rf:5,rs:5,a:2
[5/0]ababa31lf:31,rf:26,rs:4,a:10
[5/1]abaab20lf:14,lp:6,rf:8,rp:8,a:2
[5/2]aabab19lf:12,lp:7,rf:11,rp:4,a:10
[5/3]babab19lf:19,rf:15,a:17
[5/4]baaba18lf:14,ls:4,rf:8,a:2
[5/5]babaa12lf:12,rf:7,rs:3,a:10
[5/6]aabaa11lf:6,lp:1,ls:4,rf:1,rs:1,lprs:1,a:2
[6/0]abaaba24lf:14,lp:6,ls:4,rf:8,rp:8,lsrp:13,a:2
[6/1]aababa19lf:12,lp:7,rf:11,rp:4,rs:1,re:1,a:10
[6/2]ababab19lf:19,rf:15,a:17
[6/3]bababa19lf:19,rf:15,rs:3,a:17
[6/4]ababaa12lf:12,rf:7,rs:3,a:10
[6/5]baaaaa10lf:5,ls:5,a:16
[6/6]baabaa9lf:5,ls:4,rf:1,rs:1,a:2
[7/0]abababa19lf:19,rf:15,rs:3,a:17
[7/1]aababab14lf:9,lp:5,rf:8,rp:3,a:17
[7/2]abaaaaa10lf:5,ls:5,a:16
[7/3]abaabaa10lf:5,lp:1,ls:4,rf:1,rp:1,rs:1,re:1,a:2
[7/4]abaabab10lf:5,lp:5,rf:7,rp:7,a:10
[7/5]babaaba10lf:7,ls:3,a:10
[7/6]bababab10lf:10,rf:7,a:20

Considering [length 2 / frequency 0] aa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabaabaa=a⟩.