Morphocompletion for #1615 ⟨a, b | aaabaabaa=a⟩

Back:⟨a, b | aaabaabaa=a⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaba ⇒ abaaa
2. aabaaba ⇒ abaabaa
3. aababaaba ⇒ abaababaa
4. abaabaaaa ⇒ a
5. aababaabaa ⇒ abaababaaa
6. aabababaaba ⇒ abaabababaa
7. aabababaabaa ⇒ abaabababaaa
8. aababababaaba ⇒ abaababababaa
9. abaababaaaaa ⇒ aaba
10. aababababaabaa ⇒ abaababababaaa
11. abaabababaaaaa ⇒ aababa
12. aabababababaabaa ⇒ abaabababababaaa
13. abaababababaaaaa ⇒ aabababa
14. abaabababababaaaaa ⇒ aababababa
15. abaababababababaaaaa ⇒ aabababababa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aba, [3/1] aab, [3/2] bab, [3/3] baa, [3/4] aaa
Length 4:[4/0] aaba, [4/1] abaa, [4/2] abab, [4/3] baba, [4/4] aaaa, [4/5] baab, [4/6] baaa
Length 5:[5/0] ababa, [5/1] abaab, [5/2] aabab, [5/3] babab, [5/4] baaba, [5/5] babaa, [5/6] aabaa
Length 6:[6/0] abaaba, [6/1] aababa, [6/2] ababab, [6/3] bababa, [6/4] ababaa, [6/5] baaaaa, [6/6] baabaa
Length 7:[7/0] abababa, [7/1] aababab, [7/2] abaaaaa, [7/3] abaabaa, [7/4] abaabab, [7/5] babaaba, [7/6] bababab

Considering [length 2 / frequency 0] aa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabaabaa=a⟩.