Morphocompletion for #1587 ⟨a, b | aaaababaa=a⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaaba ⇒ abaaaaa
2. ababaaaaa ⇒ a
3. aababa ⇒ ababaa
4. ababaabaaaaa ⇒ aaba
5. ababaaabaaaaa ⇒ aaaba
6. ababaaaabaaaaa ⇒ aaaaba
7. ababaabaabaaaaa ⇒ aabaaba
8. ababaabaaabaaaaa ⇒ aabaaaba
9. ababaabaaaabaaaaa ⇒ aabaaaaba
10. ababaaabaabaaaaa ⇒ aaabaaba
11. ababaaabaaabaaaaa ⇒ aaabaaaba
12. ababaaabaaaabaaaaa ⇒ aaabaaaaba
13. ababaaaabaabaaaaa ⇒ aaaabaaba
14. ababaaaabaaabaaaaa ⇒ aaaabaaaba
15. ababaaaabaaaabaaaaa ⇒ aaaabaaaaba
16. ababaabaabaabaaaaa ⇒ aabaabaaba
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa122lf:106,lp:2,ls:14,rf:50,rp:13,rs:2,lsrp:13,lprs:2,a:8
[2/1]ab69lf:55,lp:14,rf:27,rp:2,a:8
[2/2]ba57lf:55,ls:2,rf:27,rs:13,a:8
[3/0]aaa81lf:66,lp:1,ls:14,rf:24,rp:8,rs:1,lsrp:8,lprs:1,a:9
[3/1]aba71lf:55,lp:14,ls:2,rf:27,rp:2,rs:13,lsrp:2,lprs:13,a:8
[3/2]baa38lf:38,rf:13,rs:1,a:8
[3/3]aab27lf:26,lp:1,rf:24,rp:5,a:8
[3/4]bab15lf:15,rf:1,a:8
[4/0]aaaa52lf:37,lp:1,ls:14,rf:9,rp:4,rs:1,lsrp:4,lprs:1,a:9
[4/1]abaa38lf:38,rf:13,rp:1,rs:1,a:8
[4/2]abab29lf:15,lp:14,rf:1,rp:1,a:8
[4/3]aaba28lf:26,lp:1,ls:1,rf:24,rp:5,rs:13,re:1,a:8
[4/4]baaa28lf:28,rf:7,a:9
[4/5]baba16lf:15,ls:1,rf:1,a:8
[4/6]aaab15lf:15,rf:14,rp:4,a:11
[5/0]ababa30lf:15,lp:14,ls:1,rf:1,rp:1,lsrp:10,a:8
[5/1]aaaaa30lf:15,lp:1,ls:14,rf:1,rs:1,lprs:1,a:9
[5/2]abaaa28lf:28,rf:7,rp:1,a:9
[5/3]aabaa24lf:24,rf:11,rp:4,a:10
[5/4]baaaa21lf:21,rf:4,a:9
[5/5]aaaba16lf:15,ls:1,rf:14,rp:4,rs:8,re:1,a:11
[5/6]babaa14lf:14,rf:1,rs:1,a:8
[6/0]ababaa28lf:14,lp:14,rf:1,rp:1,rs:1,re:1,a:8
[6/1]baaaaa28lf:14,ls:14,rf:1,rs:1,a:9
[6/2]abaaaa21lf:21,rf:4,rp:1,a:9
[6/3]aabaaa19lf:19,rf:6,rp:2,a:10
[6/4]aaabaa14lf:14,rf:6,rp:3,a:11
[6/5]abaaba10lf:10,rf:5,rs:4,a:10
[6/6]baabaa10lf:10,rf:1,a:10
[7/0]abaaaaa28lf:14,ls:14,rf:1,rp:1,rs:1,re:1,a:9
[7/1]ababaaa18lf:9,lp:9,a:9
[7/2]aabaaaa16lf:16,rf:3,rp:1,a:10
[7/3]aaabaaa12lf:12,rf:4,rp:2,a:11
[7/4]ababaab10lf:5,lp:5,a:10
[7/5]abaabaa10lf:10,rf:1,a:10
[7/6]abaaaab7lf:7,rf:3,a:13

Considering [length 5 / frequency 0] ababa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaababaa=a⟩.