Morphocompletion for #1519 ⟨a, b | ababbaabba=1⟩

Solved by morph:2/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abba ⇒ baab
2. abbaa ⇒ baaba
3. ababab ⇒ bbabaa
4. babbabaa ⇒ bbabaaba
5. abbbabaa ⇒ bbabaaab
6. abbbaab ⇒ baabbba
7. abbabaaba ⇒ babaababa
8. bbabaababa ⇒ 1
9. baabbbaba ⇒ bbabaaabb
10. bbabaaabbaba ⇒ ab
11. abbababaababa ⇒ baa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] bb, [2/3] aa
Length 3:[3/0] aba, [3/1] bab, [3/2] abb, [3/3] bba
Length 4:[4/0] baba, [4/1] bbab, [4/2] abba, [4/3] abaa
Length 5:[5/0] bbaba, [5/1] babaa, [5/2] ababa, [5/3] abbab
Length 6:[6/0] bbabaa, [6/1] abbaba, [6/2] aababa, [6/3] abaaba

Considering [length 2 / frequency 0] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ba ⇒ c
2. bccacc ⇒ 1
3. bccaa ⇒ accc
4. cbca ⇒ bcac
5. cbcca ⇒ bccac
6. cccbcc ⇒ b
7. accb ⇒ bcca
8. accbc ⇒ bccac
9. bbcca ⇒ cccb
10. bcab ⇒ cbc
11. bcacb ⇒ ccbc
12. bccab ⇒ cbcc
13. accbb ⇒ cbcc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] bc, [2/1] cc, [2/2] cb, [2/3] ca, [2/4] ac, [2/5] bb, [2/6] ab
Length 3:[3/0] bcc, [3/1] acc, [3/2] cbc, [3/3] cca, [3/4] bca, [3/5] ccb, [3/6] cab
Length 4:[4/0] bcca, [4/1] accb, [4/2] cbcc, [4/3] ccbc, [4/4] ccbb, [4/5] bbcc, [4/6] ccab
Length 5:[5/0] cccbc, [5/1] ccbcc, [5/2] bccac, [5/3] ccacc

Considering [length 4 / frequency 0] bcca=d.

Step 3

Rewriting system is complete. See a, b | ababbaabba=1⟩.