Morphocompletion for #1519 ⟨a, b | ababbaabba=1⟩

Solved by morph:2/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abba ⇒ baab
2. abbaa ⇒ baaba
3. ababab ⇒ bbabaa
4. babbabaa ⇒ bbabaaba
5. abbbabaa ⇒ bbabaaab
6. bbaababba ⇒ bbabaabab
7. abbabaaba ⇒ babaababa
8. bbabaababa ⇒ 1
9. bbabaaabbaba ⇒ ab
10. abbababaababa ⇒ baa
...

Collecting factors up to length 7 / frequency 4:

[2/0]ba35lf:28,lp:1,ls:6,rf:18,rp:4,rs:3,lsrp:3,lprs:1,lsrs:1,a:17
[2/1]ab32lf:25,lp:6,ls:1,rf:14,rp:1,rs:4,re:1,lprs:2,a:17
[2/2]bb15lf:12,lp:3,rf:4,rp:4,lprp:1,a:17
[2/3]aa12lf:9,ls:3,rf:9,rs:2,a:17
[3/0]aba21lf:16,lp:1,ls:4,rf:10,rs:3,lsrs:1,a:17
[3/1]bab16lf:14,lp:1,ls:1,rf:7,rp:1,rs:1,a:18
[3/2]bba16lf:11,lp:3,ls:2,rf:4,rp:4,lprp:1,lsrp:1,a:17
[3/3]abb13lf:8,lp:5,a:17
[4/0]baba14lf:11,ls:3,rf:6,rp:1,rs:1,a:18
[4/1]abba10lf:6,lp:3,ls:1,a:17
[4/2]bbab9lf:7,lp:2,rf:4,rp:4,a:18
[4/3]abaa8lf:6,ls:2,rf:5,rs:1,a:18
[5/0]bbaba10lf:7,lp:2,ls:1,rf:4,rp:4,a:18
[5/1]babaa8lf:6,ls:2,rf:5,rp:1,rs:1,a:18
[5/2]ababa7lf:4,lp:1,ls:2,rf:1,rs:1,a:18
[5/3]abbab6lf:4,lp:2,a:20
[6/0]bbabaa9lf:5,lp:2,ls:2,rf:4,rp:4,rs:1,re:1,lsrp:2,a:18
[6/1]abbaba7lf:4,lp:2,ls:1,a:20
[6/2]aababa4lf:2,ls:2,rf:1,rs:1,a:21
[6/3]abaaba4lf:3,ls:1,rf:3,rs:1,a:20

Considering [length 2 / frequency 0] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cccbcc ⇒ b
2. cccbb ⇒ bcbcc
3. ba ⇒ c
4. bccacc ⇒ 1
5. cbca ⇒ bcac
6. cbcca ⇒ bccac
7. accbc ⇒ bccac
8. bbcca ⇒ cccb
9. bcab ⇒ cbc
10. bcacb ⇒ ccbc
11. bccab ⇒ cbcc
12. cbcccacb ⇒ bc
13. accbb ⇒ cbcc
...

Collecting factors up to length 6 / frequency 7:

[2/0]cc18lf:14,lp:2,ls:2,rf:8,rp:2,rs:3,lprs:1,a:20
[2/1]bc15lf:10,lp:4,ls:1,rf:10,rp:5,rs:3,re:1,lsrp:1,lprs:2,a:15
[2/2]cb14lf:9,lp:3,ls:2,rf:6,rp:3,rs:1,a:15
[2/3]ca11lf:8,ls:3,rf:3,a:15
[2/4]ac7lf:5,lp:2,rf:3,rs:3,lprs:1,a:15
[2/5]bb6lf:3,lp:1,ls:2,a:38
[2/6]ab4lf:2,ls:2,a:16
[3/0]cbc9lf:5,lp:3,ls:1,rf:5,rp:3,rs:2,re:1,a:15
[3/1]bcc9lf:6,lp:2,ls:1,rf:5,rp:2,rs:3,lprs:1,a:20
[3/2]cca7lf:5,ls:2,rf:2,a:20
[3/3]bca6lf:3,lp:2,ls:1,rf:1,rp:1,lsrp:10,a:15
[3/4]acc6lf:3,lp:2,ls:1,a:26
[3/5]ccc5lf:3,lp:2,rf:1,rp:1,a:35
[3/6]cab4lf:2,ls:2,a:16
[4/0]bcca8lf:4,lp:2,ls:2,rf:2,rp:2,lsrp:10,a:20
[4/1]cbcc6lf:3,lp:2,ls:1,rf:3,rp:2,rs:3,re:2,a:20
[4/2]cacb4lf:2,ls:2,a:22
[4/3]accb4lf:2,lp:2,a:27
[4/4]ccbb4lf:2,ls:2,a:38
[4/5]cccb4lf:2,lp:2,rf:1,rp:1,rs:1,re:1,a:35
[4/6]ccbc3lf:2,ls:1,rf:1,rp:1,rs:1,re:1,a:22
[5/0]ccacb2lf:1,ls:1,a:41
[5/1]bccac2lf:1,lp:1,rf:2,rp:2,rs:2,re:2,a:20
[5/2]ccacc2lf:1,ls:1,a:26
[5/3]cccbc2lf:1,lp:1,a:35
[5/4]ccbcc2lf:1,ls:1,a:35
[5/5]cbccc2lf:1,lp:1,a:41
[5/6]bccca1lf:1,a:41

Considering [length 4 / frequency 0] bcca=d.

Step 3

Rewriting system is complete. See ⟨a, b | ababbaabba=1⟩.