Morphocompletion for #1515 ⟨a, b | abababbaba=1⟩

Solved by morph:2/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. babaab ⇒ abbaba
2. abbabaa ⇒ aababab
3. babbaba ⇒ abababb
4. baababab ⇒ abababba
5. aabbbabaa ⇒ aabababab
6. aabababbab ⇒ 1
7. baabaabbaba ⇒ abababbaaab
8. babaaababab ⇒ abbabababaa
9. babaaabbaba ⇒ aabababbaab
10. babbaabbaba ⇒ abababbbaab
11. aababababababb ⇒ baba
12. aaabababbbbabaa ⇒ aabab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] bab, [3/1] aba, [3/2] baa, [3/3] aab
Length 4:[4/0] baba, [4/1] abab, [4/2] abaa, [4/3] bbab
Length 5:[5/0] babaa, [5/1] bbaba, [5/2] babab, [5/3] abbab
Length 6:[6/0] abbaba, [6/1] ababab, [6/2] aababa, [6/3] bbabaa

Considering [length 2 / frequency 0] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccaccc ⇒ a
2. cccbcc ⇒ b
3. ccaca ⇒ aaccc
4. ccacca ⇒ acaccc
5. accbcc ⇒ 1
6. caccb ⇒ accbc
7. ccab ⇒ abcc
8. ccacb ⇒ acbcc
9. ba ⇒ c
10. bcca ⇒ accb
11. cccbca ⇒ bcaccc
12. cccbb ⇒ bcbcc
13. cccbcb ⇒ bccbcc
14. aaccb ⇒ ccac
15. accbca ⇒ caccc
16. accbb ⇒ cbcc
17. accbcb ⇒ ccbcc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cc, [2/1] cb, [2/2] ca, [2/3] ac, [2/4] bc, [2/5] bb, [2/6] ab
Length 3:[3/0] cca, [3/1] ccb, [3/2] acc, [3/3] ccc, [3/4] cbc, [3/5] bcc, [3/6] cac
Length 4:[4/0] accb, [4/1] cccb, [4/2] ccac, [4/3] ccbc, [4/4] ccbb, [4/5] cbcb, [4/6] cbca
Length 5:[5/0] accbc, [5/1] cccbc, [5/2] ccbcb, [5/3] ccbca, [5/4] ccbcc, [5/5] ccacc, [5/6] cacca

Considering [length 4 / frequency 0] accb=d.

Step 3

Rewriting system is complete. See a, b | abababbaba=1⟩.