Morphocompletion for #1513 ⟨a, b | ababababba=1⟩

Solved by morph:2/0,5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baab ⇒ abba
2. baaabb ⇒ aabbba
3. bbaaab ⇒ abbbaa
4. baaabba ⇒ abbaaab
5. bababbaa ⇒ abababab
6. baaababba ⇒ abbaaabab
7. babababba ⇒ ababababb
8. aababababb ⇒ 1
9. baaabababab ⇒ abababbabaa
10. aabababababbbaa ⇒ baaab
...

Collecting factors up to length 7 / frequency 4:

[2/0]ba37lf:27,lp:7,ls:3,rf:17,rp:1,rs:2,lprs:2,a:1
[2/1]ab27lf:24,ls:3,rf:21,rp:7,rs:4,lsrp:3,a:1
[2/2]aa19lf:15,lp:2,ls:2,rf:9,rp:1,rs:2,a:9
[2/3]bb12lf:9,lp:1,ls:2,rf:9,rs:1,a:1
[3/0]bab19lf:16,lp:2,ls:1,rf:10,rs:2,lprs:1,a:1
[3/1]baa15lf:8,lp:5,ls:2,rf:5,rp:1,rs:2,lsrp:1,lprs:1,a:9
[3/2]aba14lf:14,rf:10,rp:3,a:1
[3/3]aab12lf:8,lp:2,ls:2,rf:4,rp:1,rs:2,lprs:1,a:16
[4/0]abab15lf:14,ls:1,rf:9,rp:3,rs:2,lsrp:1,a:1
[4/1]baba12lf:10,lp:2,rf:6,a:1
[4/2]baaa9lf:5,lp:4,rf:3,rp:1,a:19
[4/3]abba7lf:4,ls:3,rf:4,rp:3,rs:1,re:1,lsrp:2,a:1
[5/0]babab13lf:10,lp:2,ls:1,rf:5,rs:1,lprs:1,a:1
[5/1]baaab10lf:5,lp:4,ls:1,rf:3,rp:1,rs:2,re:1,lprs:1,a:19
[5/2]ababa8lf:8,rf:5,rp:3,a:1
[5/3]ababb6lf:5,ls:1,rf:2,rs:1,a:1
[6/0]ababab9lf:8,ls:1,rf:5,rp:3,rs:1,lsrp:1,a:1
[6/1]bababb6lf:4,lp:1,ls:1,rf:2,rs:1,a:1
[6/2]bababa6lf:5,lp:1,rf:2,a:1
[6/3]ababba5lf:3,ls:2,rf:1,a:1

Considering [length 2 / frequency 0] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cacccc ⇒ a
2. ccccbc ⇒ b
3. caccca ⇒ aacccc
4. acccbc ⇒ 1
5. cab ⇒ abc
6. cacb ⇒ acbc
7. caccb ⇒ accbc
8. cacccb ⇒ 1
9. ba ⇒ c
10. cbcca ⇒ bccac
11. cbccca ⇒ bcccac
12. ccccbb ⇒ bcccbc
13. aacccb ⇒ caccc
14. abca ⇒ cac
15. abcca ⇒ ccac
16. abccca ⇒ cccac
17. acccbb ⇒ cccbc
...

Collecting factors up to length 6 / frequency 7:

[2/0]cc29lf:26,lp:2,ls:1,rf:16,rp:3,rs:2,a:2
[2/1]ca24lf:12,lp:6,ls:6,rf:6,rp:2,lsrp:1,a:11
[2/2]cb16lf:10,lp:2,ls:4,rf:4,a:2
[2/3]ac10lf:8,lp:2,rf:9,rp:2,rs:5,a:2
[2/4]bc9lf:7,ls:2,rf:8,rp:3,rs:5,a:2
[2/5]ab8lf:4,lp:3,ls:1,rf:1,rp:1,lsrp:10,a:14
[2/6]bb4lf:2,ls:2,a:4
[3/0]ccc16lf:13,lp:2,ls:1,rf:7,rp:2,rs:2,a:2
[3/1]ccb10lf:7,ls:3,rf:3,a:2
[3/2]cca10lf:5,ls:5,rf:4,rp:1,lsrp:1,a:18
[3/3]cac10lf:5,lp:5,rf:6,rp:2,rs:5,re:1,a:11
[3/4]acc9lf:7,lp:2,rf:3,rp:1,a:2
[3/5]cbc8lf:4,lp:2,ls:2,rf:4,rs:4,a:2
[3/6]abc6lf:3,lp:3,rf:1,rp:1,rs:1,re:1,a:14
[4/0]cccb8lf:6,ls:2,rf:2,rp:1,a:2
[4/1]cacc8lf:4,lp:4,rf:1,rp:1,a:11
[4/2]accc8lf:6,lp:2,rf:2,rs:1,a:2
[4/3]ccca6lf:3,ls:3,rf:2,rp:1,lsrp:1,a:18
[4/4]cccc6lf:3,lp:2,ls:1,rf:1,rs:1,a:3
[4/5]ccbb4lf:2,ls:2,a:4
[4/6]bcca4lf:2,ls:2,rf:1,rp:1,lsrp:10,a:21
[5/0]acccb8lf:4,lp:2,ls:2,a:2
[5/1]caccc6lf:3,lp:3,rf:1,rp:1,rs:1,re:1,a:11
[5/2]cccbb4lf:2,ls:2,a:4
[5/3]bccca4lf:2,ls:2,rf:1,rp:1,lsrp:10,a:24
[5/4]ccccb4lf:2,lp:2,a:3
[5/5]cccbc4lf:2,ls:2,rf:2,rp:1,rs:2,re:1,a:2
[5/6]abccc2lf:1,lp:1,a:24

Considering [length 5 / frequency 0] acccb=d.

Step 3

Rewriting system is complete. See ⟨a, b | ababababba=1⟩.