Morphocompletion for #1426 ⟨a, b | aababbaaab=1⟩

Back:⟨a, b | aababbaaab=1⟩

Solved by morph:4/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaaab ⇒ aababba
2. aababbaaab ⇒ 1
3. abbaaaababba ⇒ aababbabaaab
4. abbaaaabaababb ⇒ abba
5. aababbabaaabaab ⇒ abbaa
6. abbaaaaabaababb ⇒ abbaa
7. abbaaaabaababba ⇒ abbaa
8. abbaaaaaabaababb ⇒ abbaaa
9. abbaabaaaabaababb ⇒ abbaaba
10. abbaaaaaaabaababb ⇒ abbaaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] abb, [3/1] aab, [3/2] aaa, [3/3] baa, [3/4] aba, [3/5] bba, [3/6] bab
Length 4:[4/0] abba, [4/1] aaba, [4/2] babb, [4/3] aaaa, [4/4] aaab, [4/5] baaa, [4/6] abaa
Length 5:[5/0] abbaa, [5/1] ababb, [5/2] aabab, [5/3] aabaa, [5/4] aaaba, [5/5] bbaaa, [5/6] abaab
Length 6:[6/0] aababb, [6/1] abbaaa, [6/2] aabaab, [6/3] aaabaa, [6/4] aaaaba, [6/5] bbaaaa, [6/6] abaaba
Length 7:[7/0] abbaaaa, [7/1] baababb, [7/2] aaabaab, [7/3] aababba, [7/4] aaaabaa, [7/5] aabaaba, [7/6] abaabab

Considering [length 4 / frequency 2] babb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababbaaab=1⟩.