Morphocompletion for #1378 ⟨a, b | aaabbbaaab=1⟩

Solved by morph:3/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. bbaaa ⇒ aaabb
2. baaabbba ⇒ abaaabbb
3. aaabbbbba ⇒ babaaabbb
4. aaabaaabbb ⇒ 1
5. baaabaaabb ⇒ 1
6. aaabbabaaabbb ⇒ bba
7. baaabaaaaaabb ⇒ aaa
8. aaabaaaaaabbbb ⇒ baaa
9. aaabbaabaaabbb ⇒ bbaa
10. aaabbbbabaaabbb ⇒ bbbba
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa48lf:41,lp:6,ls:1,rf:11,rp:2,rs:3,lsrp:1,lprs:2,a:4
[2/1]bb33lf:25,lp:1,ls:7,rf:10,rp:3,rs:3,lsrp:3,lprs:1,a:4
[2/2]ba21lf:16,lp:3,ls:2,rf:7,rp:2,rs:2,lsrp:1,a:4
[2/3]ab19lf:19,rf:5,rp:1,a:4
[3/0]aaa30lf:23,lp:6,ls:1,rf:5,rp:2,rs:2,re:1,lsrp:1,lprs:1,a:4
[3/1]aab17lf:17,rf:3,a:4
[3/2]bbb17lf:12,ls:5,rf:4,rp:1,rs:2,lsrp:1,a:27
[3/3]baa15lf:12,lp:3,rf:4,rp:1,rs:1,a:4
[4/0]aaab22lf:16,lp:6,rf:3,rp:1,a:4
[4/1]baaa15lf:11,lp:3,ls:1,rf:3,rp:1,rs:1,re:1,a:4
[4/2]aabb14lf:12,ls:2,rf:3,rs:1,a:4
[4/3]abbb12lf:8,ls:4,rf:2,rs:2,a:27
[5/0]aaabb18lf:12,lp:4,ls:2,rf:3,rp:1,rs:1,re:1,a:4
[5/1]aabbb12lf:8,ls:4,rf:2,rs:2,a:27
[5/2]baaab11lf:8,lp:3,rf:2,a:20
[5/3]abaaa7lf:7,rf:2,rp:1,a:20
[6/0]aaabbb14lf:8,lp:2,ls:4,rf:2,rs:2,lprs:1,a:27
[6/1]baaabb8lf:6,lp:1,ls:1,rf:2,a:20
[6/2]aaabaa6lf:4,lp:2,a:20
[6/3]aabaaa5lf:5,a:20

Considering [length 3 / frequency 0] aaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ca ⇒ ac
2. cbb ⇒ bbc
3. aaa ⇒ c
4. cbcb ⇒ bcbc
5. cbccb ⇒ bccbc
6. bcbcb ⇒ bbcbc
7. bbbcbc ⇒ 1
8. bcbccb ⇒ bbccbc
9. bbbcba ⇒ abbbcb
10. bbbcbac ⇒ a
11. bcbcccb ⇒ bbcccbc
12. bbccbcb ⇒ c
13. bbbbccbc ⇒ cb
14. bbbcbaac ⇒ aa
15. bbbbcccbc ⇒ ccb
16. bbbcbabbc ⇒ abb
...

Collecting factors up to length 6 / frequency 7:

[2/0]cb29lf:20,lp:3,ls:6,rf:8,rp:1,rs:3,re:1,a:6
[2/1]bb28lf:19,lp:8,ls:1,rf:7,rp:4,rs:1,lsrp:10,lprs:1,a:6
[2/2]bc28lf:21,lp:3,ls:4,rf:12,rp:2,rs:6,lprs:3,a:6
[2/3]cc8lf:8,rf:5,rp:1,a:9
[2/4]aa5lf:3,lp:1,ls:1,rf:1,rp:1,rs:1,re:1,a:1
[2/5]ba5lf:4,ls:1,a:18
[2/6]ac4lf:2,ls:2,rf:1,rp:1,rs:1,re:1,a:3
[3/0]bcb17lf:11,lp:3,ls:3,rf:3,rp:1,rs:1,lsrp:10,a:6
[3/1]bbb16lf:9,lp:7,rf:1,a:10
[3/2]cbc14lf:9,lp:2,ls:3,rf:5,rs:5,lprs:11,a:6
[3/3]bbc11lf:9,lp:1,ls:1,rf:5,rp:4,rs:1,re:1,a:6
[3/4]ccb9lf:6,ls:3,rf:4,rp:1,rs:1,re:1,a:9
[3/5]bcc6lf:6,rf:3,rp:1,a:9
[3/6]cba5lf:4,ls:1,a:18
[4/0]bbbc12lf:7,lp:5,rf:1,a:10
[4/1]bcbc8lf:4,lp:3,ls:1,rf:2,rp:1,rs:2,re:1,lprs:10,a:6
[4/2]bccb6lf:4,ls:2,rf:2,rp:1,lsrp:10,a:9
[4/3]bcba5lf:4,ls:1,a:18
[4/4]bbcb5lf:5,rf:2,rp:1,rs:1,a:6
[4/5]ccbc5lf:3,ls:2,rf:3,rs:3,a:9
[4/6]bbbb4lf:2,lp:2,a:10
[5/0]bbbcb10lf:5,lp:5,rf:1,rs:1,lprs:10,a:16
[5/1]bbcba5lf:4,ls:1,a:18
[5/2]bbbbc4lf:2,lp:2,a:10
[5/3]bcbcc4lf:2,lp:2,a:25
[5/4]bbccb3lf:2,lp:1,rf:1,rp:1,a:9
[5/5]bcccb3lf:2,ls:1,rf:1,a:17
[5/6]bccbc3lf:2,ls:1,rf:2,rp:1,rs:2,re:1,a:9

Considering [length 3 / frequency 0] bcb=d.

Step 3

Rewriting system is complete. See ⟨a, b | aaabbbaaab=1⟩.