Morphocompletion for #1328 ⟨a, b | aaaabbabba=1⟩

Solved by morph:4/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbaaa ⇒ bbaaaaaaa
2. bbabbaaaaa ⇒ 1
3. abbabb ⇒ bbabba
4. bbabbbbaaaaaaaa ⇒ aaabb
5. bbabbaabbaaaa ⇒ abb
6. bbabbaaabbaaaa ⇒ aabb
7. abbbbabba ⇒ bbabbaabb
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa31lf:25,lp:1,ls:5,rf:10,rp:2,rs:1,lsrp:2,lprs:1,lsrs:1,a:9
[2/1]bb24lf:19,lp:4,ls:1,rf:9,rp:3,rs:4,lsrp:1,lprs:3,a:9
[2/2]ba15lf:14,ls:1,rf:5,rs:1,a:9
[2/3]ab13lf:11,lp:2,rf:6,rp:1,a:9
[3/0]aaa23lf:17,lp:1,ls:5,rf:6,rp:1,rs:1,lsrp:1,lprs:1,lsrs:1,a:9
[3/1]bba19lf:14,lp:4,ls:1,rf:5,rp:3,rs:1,lsrp:1,a:9
[3/2]abb14lf:11,lp:2,ls:1,rf:6,rp:1,rs:4,re:1,lprs:1,a:9
[3/3]baa7lf:7,rf:2,a:9
[4/0]aaaa15lf:10,lp:1,ls:4,rf:4,rs:1,lprs:1,a:9
[4/1]bbab10lf:6,lp:4,rf:2,rp:2,a:15
[4/2]abba10lf:8,lp:1,ls:1,rf:2,rs:1,lprs:1,a:9
[4/3]babb7lf:6,ls:1,rf:2,a:15
[5/0]bbabb11lf:6,lp:4,ls:1,rf:2,rp:2,lsrp:10,a:15
[5/1]bbaaa7lf:6,ls:1,rf:1,rp:1,lsrp:1,a:9
[5/2]aaaaa7lf:5,ls:2,rf:3,rs:1,a:9
[5/3]abbaa6lf:6,rf:1,a:9
[6/0]bbabba8lf:4,lp:3,ls:1,rf:2,rp:2,rs:1,re:1,lsrp:1,a:15
[6/1]abbaaa6lf:5,ls:1,a:9
[6/2]bbaaaa6lf:4,ls:2,rf:1,rp:1,a:9
[6/3]aaaaaa4lf:3,ls:1,rf:2,rs:1,a:9

Considering [length 4 / frequency 0] aaaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ac ⇒ ca
2. aaaa ⇒ c
3. cbb ⇒ bbc
4. cabb ⇒ abbc
5. caabb ⇒ aabbc
6. caaabb ⇒ aaabbc
7. abbcab ⇒ babbca
8. bbabbcc ⇒ aaa
9. bbabbca ⇒ 1
10. cbbabbc ⇒ aaa
11. cbbabba ⇒ 1
12. abbabb ⇒ bbabba
13. abbabbc ⇒ 1
14. cabbabb ⇒ 1
15. bbcbabbca ⇒ cb
...

Collecting factors up to length 6 / frequency 7:

[2/0]bb30lf:21,lp:3,ls:6,rf:7,rp:2,lsrp:11,a:2
[2/1]ab20lf:16,lp:3,ls:1,rf:5,rp:1,a:2
[2/2]ca13lf:7,lp:4,ls:2,rf:2,rp:1,rs:2,re:1,a:3
[2/3]ba10lf:9,ls:1,rf:3,rp:1,rs:1,a:2
[2/4]bc9lf:7,ls:2,rf:5,rs:4,a:4
[2/5]aa8lf:6,lp:1,ls:1,rf:7,rp:4,rs:2,a:1
[2/6]cb7lf:4,lp:3,rf:1,rp:1,rs:1,re:1,a:2
[3/0]abb23lf:15,lp:3,ls:5,rf:5,rp:1,lsrp:10,a:2
[3/1]bba11lf:8,lp:2,ls:1,rf:2,rp:1,rs:1,a:2
[3/2]bbc10lf:7,lp:1,ls:2,rf:5,rp:1,rs:4,re:1,a:4
[3/3]bab8lf:8,rf:2,rp:1,a:2
[3/4]cab6lf:3,lp:2,ls:1,a:9
[3/5]bca5lf:3,ls:2,rf:1,rs:1,a:24
[3/6]aaa5lf:3,lp:1,ls:1,rf:3,rp:3,rs:2,re:2,a:1
[4/0]babb10lf:8,ls:2,rf:2,rp:1,a:2
[4/1]bbab9lf:7,lp:2,rf:1,rp:1,a:2
[4/2]abbc9lf:6,lp:1,ls:2,rf:4,rp:1,rs:3,re:1,a:4
[4/3]abba7lf:4,lp:2,ls:1,rf:1,rs:1,lprs:1,a:2
[4/4]bbca5lf:3,ls:2,rf:1,rs:1,a:24
[4/5]aabb4lf:2,ls:2,rf:2,rp:1,lsrp:10,a:29
[4/6]cbba4lf:2,lp:2,a:2
[5/0]bbabb11lf:7,lp:2,ls:2,rf:1,rp:1,lsrp:10,a:2
[5/1]babbc7lf:5,ls:2,rf:1,rp:1,a:4
[5/2]abbca6lf:3,lp:1,ls:2,rf:1,rs:1,lprs:10,a:24
[5/3]abbab5lf:3,lp:2,a:9
[5/4]cbbab4lf:2,lp:2,a:2
[5/5]babba2lf:1,ls:1,rf:1,rs:1,a:2
[5/6]bbcab2lf:1,ls:1,a:27

Considering [length 3 / frequency 0] abb=d.

Step 3

Rewriting system is complete. See ⟨a, b | aaaabbabba=1⟩.