Morphocompletion for #1241 ⟨a, b | abaab=aaba⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaab ⇒ aaba
2. abaaaba ⇒ aabaaab
3. abaaaaba ⇒ aaabaaabb
4. aabaaabbaab ⇒ aaabaaabba
5. abaaaaaba ⇒ aaabaaabbab
6. aaabaaabbbaab ⇒ aaabaaabbaba
7. aabaaaabbaab ⇒ aaaabaaabbba
8. abaaaaaaba ⇒ aaabaaabbabab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa32lf:29,lp:3,rf:29,rp:8,lprp:3
[2/1]ab28lf:19,lp:5,ls:4,rf:19,rs:3,lprs:3
[2/2]ba19lf:15,ls:4,rf:15,rs:4
[2/3]bb4lf:4,rf:7,rs:1,a:3
[3/0]aba21lf:12,lp:5,ls:4,rf:10,rs:2,lprs:1
[3/1]aab20lf:14,lp:2,ls:4,rf:15,rp:2,rs:1,lsrp:1
[3/2]aaa16lf:15,lp:1,rf:14,rp:6,lprp:1,a:1
[3/3]baa11lf:11,rf:7
[3/4]bba3lf:3,rf:5,rs:2,a:4
[3/5]abb3lf:3,rf:6,rs:1,a:3
[3/6]bbb1lf:1,rf:1,a:10
[4/0]abaa13lf:8,lp:5,rf:7
[4/1]aaba13lf:7,lp:2,ls:4,rf:8,rp:2,rs:1,re:1,lsrp:1
[4/2]aaab9lf:8,lp:1,rf:13,rp:5,rs:1,lprp:1,a:1
[4/3]baab8lf:4,ls:4
[4/4]aaaa7lf:7,rf:1,rp:1,a:3
[4/5]baaa7lf:7,rf:7,a:1
[4/6]bbaa3lf:3,a:4
[5/0]abaaa11lf:7,lp:4,rf:7,a:1
[5/1]aaaba10lf:5,lp:1,ls:4,rf:6,rp:5,lprp:1,lsrp:3,a:1
[5/2]bbaab6lf:3,ls:3,a:4
[5/3]aabaa5lf:3,lp:2,rf:7,rp:1,a:1
[5/4]baaaa4lf:4,a:3
[5/5]aaaab4lf:4,rf:1,rp:1,a:3
[5/6]aaaaa3lf:3,a:9
[6/0]abaaaa7lf:4,lp:3,a:3
[6/1]aaaaba6lf:3,ls:3,rf:1,rp:1,a:3
[6/2]aabaaa5lf:3,lp:2,rf:7,rp:1,a:1
[6/3]abaaab4lf:3,lp:1,rf:7,rs:1,lprs:10,a:1
[6/4]abbaab4lf:2,ls:2,a:4
[6/5]baaaaa2lf:2,a:9
[6/6]aaabaa2lf:1,lp:1,rf:6,rp:5,lprp:1,a:3
[7/0]abaaaaa4lf:2,lp:2,a:9
[7/1]aaaaaba4lf:2,ls:2,a:9
[7/2]aabbaab4lf:2,ls:2,a:4
[7/3]abaaaab3lf:2,lp:1,a:3
[7/4]aabaaab3lf:2,lp:1,rf:7,rp:1,rs:1,re:1,a:1
[7/5]aabaaaa2lf:1,lp:1,a:23
[7/6]aaabaaa2lf:1,lp:1,rf:6,rp:5,lprp:1,a:3

Considering [length 4 / frequency 0] abaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaab=aaba⟩.