Morphocompletion for #1241 ⟨a, b | abaab=aaba

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaab ⇒ aaba
2. abaaaba ⇒ aabaaab
3. abaaaaba ⇒ aaabaaabb
4. aabaaabbaab ⇒ aaabaaabba
5. abaaaaaba ⇒ aaabaaabbab
6. aaabaaabbbaab ⇒ aaabaaabbaba
7. aabaaaabbaab ⇒ aaaabaaabbba
8. abaaaaaaba ⇒ aaabaaabbabab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] aaa, [3/3] baa, [3/4] bba, [3/5] abb, [3/6] bbb
Length 4:[4/0] abaa, [4/1] aaba, [4/2] aaab, [4/3] baab, [4/4] aaaa, [4/5] baaa, [4/6] bbaa
Length 5:[5/0] abaaa, [5/1] aaaba, [5/2] bbaab, [5/3] aabaa, [5/4] baaaa, [5/5] aaaab, [5/6] aaaaa
Length 6:[6/0] abaaaa, [6/1] aaaaba, [6/2] aabaaa, [6/3] abaaab, [6/4] abbaab, [6/5] baaaaa, [6/6] aaabaa
Length 7:[7/0] abaaaaa, [7/1] aaaaaba, [7/2] aabbaab, [7/3] abaaaab, [7/4] aabaaab, [7/5] aabaaaa, [7/6] aaabaaa

Considering [length 4 / frequency 0] abaa=c.

Step 2

Rewriting system is complete. See a, b | abaab=aaba.