| Back: | ⟨a, b | aabba=abab⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabba ⇒ abab |
| 2. | abababba ⇒ ababbab |
| 3. | ababbababba ⇒ ababbabbab |
| 4. | ababbabbabba ⇒ ababbabbbab |
| 5. | ababbabbbabba ⇒ ababbabbbbab |
| 6. | ababbabbababba ⇒ ababbabbbabb |
| 7. | ababbabbbabbba ⇒ ababbabbabbbab |
| 8. | ababbabbbbabba ⇒ ababbabbbbbab |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ba, [2/1] ab, [2/2] bb, [2/3] aa |
|---|---|
| Length 3: | [3/0] bba, [3/1] bab, [3/2] abb, [3/3] aba, [3/4] bbb, [3/5] aab |
| Length 4: | [4/0] abba, [4/1] babb, [4/2] abab, [4/3] bbab, [4/4] bbba, [4/5] abbb, [4/6] baba |
| Length 5: | [5/0] babba, [5/1] ababb, [5/2] bbabb, [5/3] abbab, [5/4] babbb, [5/5] abbba, [5/6] bbbab |
| Length 6: | [6/0] ababba, [6/1] bbabba, [6/2] babbab, [6/3] abbabb, [6/4] bbabbb, [6/5] babbba, [6/6] bbbabb |
| Length 7: | [7/0] ababbab, [7/1] babbabb, [7/2] bababba, [7/3] bbbabba, [7/4] bbabbba, [7/5] abbabba, [7/6] abbabbb |
Considering [length 4 / frequency 0] abba=c.
Rewriting system is complete. See ⟨a, b | aabba=abab⟩.