Morphocompletion for #1204 ⟨a, b | aabaa=baab⟩

Solved by morph:2/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaa ⇒ baab
2. baabbaa ⇒ aabbaab
3. baababaa ⇒ aababaab
4. aaaabbaab ⇒ baabbbaa
5. aaaababaab ⇒ baabbabaa
6. baabbbaaaa ⇒ aaaabbbaab
7. aabbaabbbaa ⇒ bbaabbbaab
8. baabbabaaaa ⇒ aaaababbaab
9. aaaaaabbbaab ⇒ baabbbbaaaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa42lf:31,lp:5,ls:6,rf:23,rp:4,rs:3,lsrp:4,lprs:3
[2/1]ba21lf:17,lp:4,rf:16,rp:4
[2/2]ab19lf:16,ls:3,rf:17,rs:6
[2/3]bb10lf:10,rf:13,rp:1,a:1
[3/0]baa22lf:14,lp:4,ls:4,rf:13,rp:4,rs:2,lsrp:1
[3/1]aab18lf:13,lp:2,ls:3,rf:14,rp:2,rs:6,lprs:2
[3/2]aaa17lf:12,lp:3,ls:2,rf:6,rp:2,rs:1,lsrp:2,lprs:1,a:3
[3/3]bba7lf:7,rf:8,rp:1,a:1
[4/0]baab15lf:8,lp:4,ls:3,rf:10,rp:4,rs:6,re:1,lsrp:3,lprs:4
[4/1]aaaa12lf:7,lp:3,ls:2,rf:3,rp:2,rs:1,lsrp:2,lprs:1,a:3
[4/2]bbaa8lf:6,ls:2,rf:7,rp:1,rs:1,lsrp:1,a:1
[4/3]aabb8lf:7,lp:1,rf:6,rp:1,a:1
[5/0]baabb7lf:4,lp:3,rf:4,rp:3,a:1
[5/1]bbaab5lf:3,ls:2,rf:5,rp:1,rs:4,a:1
[5/2]aabba5lf:4,lp:1,rf:2,rp:1,a:1
[5/3]aaaab5lf:3,lp:2,rf:2,rp:2,a:3
[6/0]aabbaa5lf:3,lp:1,ls:1,rf:1,rp:1,lsrp:10,a:1
[6/1]baabba4lf:2,lp:2,rf:1,rp:1,a:1
[6/2]abbbaa4lf:3,ls:1,rf:3,rs:1,a:3
[6/3]baabbb3lf:2,lp:1,rf:3,rp:2,a:3

Considering [length 2 / frequency 0] aa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aa ⇒ c
2. ca ⇒ ac
3. cbc ⇒ bcb
4. cbac ⇒ bcba
5. cbbcb ⇒ bcbbc
6. cbabcb ⇒ bcbabc
7. cbbbcb ⇒ bcbbcc
8. cbabbcb ⇒ bcbabcc
9. cbbbbcb ⇒ bcbbccc
10. cbabbbcb ⇒ bcbabccc
11. cbbbbbcb ⇒ bcbbcccc
12. cbabbbbcb ⇒ bcbabcccc
13. cbbbbbbcb ⇒ bcbbccccc
14. cbabbbbbcb ⇒ bcbabccccc
15. cbbbbbbbcb ⇒ bcbbcccccc
16. cbabbbbbbcb ⇒ bcbabcccccc
17. cbbbbbbbbcb ⇒ bcbbccccccc
18. cbabbbbbbbcb ⇒ bcbabccccccc
19. cbbbbbbbbbcb ⇒ bcbbcccccccc
20. cbabbbbbbbbcb ⇒ bcbabcccccccc
...

Collecting factors up to length 6 / frequency 7:

[2/0]cb68lf:34,lp:18,ls:16,rf:18,rs:1,lprs:10,a:2
[2/1]bb64lf:64,rf:8,a:4
[2/2]bc18lf:17,ls:1,rf:34,rp:18,rs:2,lsrp:10,a:2
[2/3]ba9lf:9,rf:9,rs:1,a:5
[2/4]ab8lf:8,rf:8,a:6
[2/5]ac2lf:1,ls:1,rf:1,rp:1,rs:1,re:1,a:3
[2/6]cc0rf:56,rs:14,a:8
[3/0]bbb49lf:49,a:8
[3/1]bcb32lf:16,ls:16,rf:18,rp:18,rs:1,re:1,lsrp:16,a:2
[3/2]cba18lf:9,lp:9,rf:9,rs:1,lprs:10,a:5
[3/3]cbb16lf:8,lp:8,rf:8,a:4
[3/4]bbc15lf:15,rf:8,rs:1,a:4
[3/5]bab8lf:8,rf:8,a:6
[3/6]abb7lf:7,a:10
[4/0]bbbb36lf:36,a:13
[4/1]bbcb30lf:15,ls:15,a:4
[4/2]cbab16lf:8,lp:8,rf:8,a:6
[4/3]cbbb14lf:7,lp:7,a:8
[4/4]bbbc13lf:13,a:8
[4/5]babb7lf:7,a:10
[4/6]abbb6lf:6,a:14
[5/0]bbbcb26lf:13,ls:13,a:8
[5/1]bbbbb25lf:25,a:17
[5/2]cbabb14lf:7,lp:7,a:10
[5/3]cbbbb12lf:6,lp:6,a:13
[5/4]bbbbc11lf:11,a:13
[5/5]babbb6lf:6,a:14
[5/6]abbbb5lf:5,a:18

Considering [length 2 / frequency 0] cb=d.

Step 3

Rewriting system is complete. See ⟨a, b | aabaa=baab⟩.