Morphocompletion for #1137 ⟨a, b | abbbba=bab

Solved by morph:2/1,2/1,2/1,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbba ⇒ bab
2. abbbbbab ⇒ babbbbba
3. aabbbbbbab ⇒ babbbbbbaa
4. ababbbbbbab ⇒ babbbbbbaba
5. bbbbabbbbbaa ⇒ abbbbbbab
6. abbabbbbbbab ⇒ babbbbbbabba
7. babbbbbbaabbba ⇒ aabbbbbbbab
8. abbbbbbabbbbba ⇒ babbbbbbabb
9. babbbbbbababbba ⇒ ababbbbbbbab
...

Collecting factors up to length 4, frequency 3:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba
Length 3:[3/0] bbb, [3/1] bab, [3/2] bba

Considering [length 2 / frequency 1] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cbbba ⇒ bc
3. cbbbc ⇒ bcb
4. bcbbbba ⇒ cbbbbc
5. cbbbbcb ⇒ bcbbbbc
6. ccbbbba ⇒ acbbbbc
7. bcbbbbbaa ⇒ acbbbbbc
8. bcbbbbbca ⇒ ccbbbbbc
9. acbbbbbcb ⇒ bcbbbbbac
10. cbbcbbbbc ⇒ bcbbbbba
11. ccbbbbbaa ⇒ aacbbbbbc
12. ccbbbbbcb ⇒ bcbbbbbcc
13. ccbbbbbca ⇒ accbbbbbc
14. bbbcbbbbca ⇒ cbbbbbc
15. bbbcbbbbcc ⇒ cbbbbbcb
16. bcbbbbbcba ⇒ cbcbbbbbc
17. acbcbbbbbc ⇒ bcbbbbbcca
18. cbcbbbbbcb ⇒ bcbbbbbcbc
19. bcbbbbbcbca ⇒ ccbcbbbbbc
20. bcbbbbbccaa ⇒ acccbbbbbc
...

Collecting factors up to length 5, frequency 3:

Length 2:[2/0] bb, [2/1] cb, [2/2] bc
Length 3:[3/0] bbb, [3/1] bcb, [3/2] cbb
Length 4:[4/0] bbbb, [4/1] cbbb, [4/2] bbbc

Considering [length 2 / frequency 1] cb=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cb ⇒ d
3. dbba ⇒ bc
4. dbbc ⇒ bd
5. dbbd ⇒ bdb
6. bdbbba ⇒ dbbbc
7. bdbbbc ⇒ dbbbd
8. cdbbba ⇒ adbbbc
9. cdbbbc ⇒ adbbbd
10. dbbbdb ⇒ bdbbbd
11. ddbbba ⇒ adbbbd
12. ddbbbc ⇒ cdbbbd
13. bdbbbba ⇒ ddbbbd
14. cdbbbba ⇒ addbbbd
15. dbdbbbd ⇒ bdbbbbc
16. ddbbbba ⇒ cddbbbd
17. ddbbbda ⇒ adbbbbc
18. ddbbbdc ⇒ adbbbbd
19. bbdbbbda ⇒ dbbbbc
20. bbdbbbdc ⇒ dbbbbd
...

Collecting factors up to length 4, frequency 3:

Length 2:[2/0] bb, [2/1] db, [2/2] bd
Length 3:[3/0] dbb, [3/1] bbb, [3/2] bba

Considering [length 2 / frequency 1] db=e.

Step 4

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. cb ⇒ d
3. db ⇒ e
4. eba ⇒ bc
5. ebc ⇒ bd
6. ebd ⇒ be
7. ebe ⇒ beb
8. bebba ⇒ ebbc
9. bebbc ⇒ ebbd
10. bebbd ⇒ ebbe
11. cebba ⇒ aebbc
12. cebbc ⇒ aebbd
13. cebbd ⇒ aebbe
14. debba ⇒ aebbd
15. debbc ⇒ aebbe
16. debbd ⇒ cebbe
17. ebbeb ⇒ bebbe
18. eebba ⇒ aebbe
19. eebbc ⇒ cebbe
20. eebbd ⇒ debbe
...

Collecting factors up to length 7, frequency 2:

Length 2:[2/0] eb, [2/1] bb
Length 3:[3/0] ebb, [3/1] beb
Length 4:[4/0] ebbd, [4/1] ebbc
Length 5:[5/0] debbe, [5/1] cebbe

Considering [length 2 / frequency 0] eb=f.

Step 5

Rewriting system is complete. See a, b | abbbba=bab.