Morphocompletion for #1131 ⟨a, b | abbaab=aba

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaab ⇒ aba
2. ababaaa ⇒ abaaaab
3. ababaab ⇒ abaa
4. abaabaaa ⇒ abaaaaab
5. abaabaab ⇒ abaaa
6. abaaabaaa ⇒ abaaaaaab
7. abaaabaab ⇒ abaaaa
8. abaaaabaaa ⇒ abaaaaaaab
9. abaaaabaab ⇒ abaaaaa
10. abaaaaabaaa ⇒ abaaaaaaaab
11. abaaaaabaab ⇒ abaaaaaa
12. abaaaabbaaa ⇒ abaaaaaaabb
13. abaaaaaabaab ⇒ abaaaaaaa
14. abaaaabbbaab ⇒ abaaaabba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] aaa, [3/2] aab, [3/3] baa, [3/4] abb, [3/5] bba, [3/6] bab
Length 4:[4/0] abaa, [4/1] baaa, [4/2] baab, [4/3] aaaa, [4/4] aaba, [4/5] aaab, [4/6] abab
Length 5:[5/0] abaaa, [5/1] abaab, [5/2] aabaa, [5/3] baaaa, [5/4] aaaba, [5/5] aaaab, [5/6] bbaab
Length 6:[6/0] abaaaa, [6/1] aabaab, [6/2] aabaaa, [6/3] aaabaa, [6/4] aaaaba, [6/5] baaaab, [6/6] ababaa
Length 7:[7/0] abaaaab, [7/1] aaabaab, [7/2] abaaaaa, [7/3] aaabaaa, [7/4] aaaabaa, [7/5] abaabaa, [7/6] abaaaba

Considering [length 6 / frequency 1] aabaab=c.

Step 2

Rewriting system is complete. See a, b | abbaab=aba.