Morphocompletion for #1131 ⟨a, b | abbaab=aba⟩

Solved by morph:6/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaab ⇒ aba
2. ababaaa ⇒ abaaaab
3. ababaab ⇒ abaa
4. abaabaaa ⇒ abaaaaab
5. abaabaab ⇒ abaaa
6. abaaabaaa ⇒ abaaaaaab
7. abaaabaab ⇒ abaaaa
8. abaaaabaaa ⇒ abaaaaaaab
9. abaaaabaab ⇒ abaaaaa
10. abaaaaabaaa ⇒ abaaaaaaaab
11. abaaaaabaab ⇒ abaaaaaa
12. abaaaaaabaab ⇒ abaaaaaaa
13. abaaaabbbaab ⇒ abaaaabba
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab54lf:33,lp:13,ls:8,rf:19,rp:13,rs:5,lprp:13,lsrp:8,lprs:5
[2/1]aa51lf:46,ls:5,rf:49,rs:6
[2/2]ba25lf:25,rf:14,rs:2
[2/3]bb3lf:3,rf:1
[3/0]aba35lf:23,lp:12,rf:13,rp:13,rs:1,re:1,lprp:12
[3/1]aaa28lf:23,ls:5,rf:37,rs:5,a:2
[3/2]aab26lf:18,ls:8,rf:6,rs:5
[3/3]baa23lf:23,rf:12,rs:1
[3/4]abb3lf:2,lp:1,rf:1
[3/5]bba2lf:2,rf:1,rs:1
[3/6]bab2lf:2,a:1
[4/0]abaa31lf:21,lp:10,rf:12,rp:12,rs:1,re:1,lprp:10,a:1
[4/1]baab18lf:10,ls:8
[4/2]baaa18lf:13,ls:5,rf:11,rs:1,a:2
[4/3]aaaa10lf:10,rf:26,rs:4,a:3
[4/4]aaba9lf:9,a:2
[4/5]aaab8lf:8,rf:6,rs:5,a:3
[4/6]abab4lf:2,lp:2,a:1
[5/0]abaaa26lf:13,lp:8,ls:5,rf:11,rp:11,rs:1,re:1,lprp:8,lsrp:5,a:2
[5/1]abaab16lf:8,lp:2,ls:6,a:1
[5/2]aabaa9lf:9,a:2
[5/3]aaaba7lf:7,a:3
[5/4]baaaa6lf:6,rf:10,rs:1,a:3
[5/5]aaaab6lf:6,rf:6,rs:5,a:4
[5/6]bbaab4lf:2,ls:2
[6/0]abaaaa12lf:6,lp:6,rf:10,rp:10,rs:1,re:1,lprp:6,a:3
[6/1]aabaab10lf:5,ls:5,a:2
[6/2]aabaaa8lf:4,ls:4,a:6
[6/3]aaabaa7lf:7,a:3
[6/4]aaaaba5lf:5,a:5
[6/5]ababaa4lf:2,lp:2,a:1
[6/6]abaaba4lf:2,lp:2,a:2
[7/0]aaabaab8lf:4,ls:4,a:3
[7/1]abaaaab6lf:3,lp:3,rf:2,rp:2,rs:1,re:1,lprp:1,a:4
[7/2]abaaaaa6lf:3,lp:3,rf:7,rp:7,rs:1,re:1,lprp:3,a:5
[7/3]aaabaaa6lf:3,ls:3,a:7
[7/4]aaaabaa5lf:5,a:5
[7/5]abaabaa4lf:2,lp:2,a:2
[7/6]abaaaba4lf:2,lp:2,a:3

Considering [length 6 / frequency 1] aabaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbaab=aba⟩.