| Back: | ⟨a, b | ababba=bab⟩ |
|---|
Solved by morph:3/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababba ⇒ bab |
| 2. | aababbbab ⇒ babbba |
| 3. | babbabba ⇒ ababbbab |
| 4. | babbbaabba ⇒ aababbbbab |
| 5. | ababababbbab ⇒ babbbabba |
| 6. | ababbbabbba ⇒ babababbbab |
| 7. | aaababababbbbab ⇒ babbbabaabba |
| 8. | ababaababbbbab ⇒ babbbbaabba |
| 9. | babbbabbaabba ⇒ ababababbbbab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 38 | lf:30,lp:4,ls:4,rf:24,rp:2,rs:5,lprs:2 |
|---|---|---|---|
| [2/1] | ba | 37 | lf:29,lp:3,ls:5,rf:25,rp:6,rs:4,lsrp:2 |
| [2/2] | bb | 24 | lf:24,rf:22 |
| [2/3] | aa | 8 | lf:6,lp:2,rf:3,rp:1,a:2 |
| [3/0] | bab | 28 | lf:21,lp:3,ls:4,rf:19,rp:6,rs:5,re:1,lsrp:4,lprs:3 |
| [3/1] | bba | 19 | lf:14,ls:5,rf:11,rs:4 |
| [3/2] | aba | 16 | lf:12,lp:4,rf:8,rp:2 |
| [3/3] | abb | 14 | lf:14,rf:11 |
| [3/4] | bbb | 10 | lf:10,rf:11,a:1 |
| [3/5] | aab | 6 | lf:5,lp:1,rf:3,rp:1,a:2 |
| [3/6] | baa | 3 | lf:3,rf:2,a:6 |
| [4/0] | babb | 15 | lf:12,lp:3,rf:9,rp:4 |
| [4/1] | abab | 15 | lf:11,lp:4,rf:7,rp:2 |
| [4/2] | bbab | 11 | lf:7,ls:4,rf:6,rs:4,a:1 |
| [4/3] | abba | 10 | lf:6,ls:4,rf:3,rs:3 |
| [4/4] | bbba | 9 | lf:8,ls:1,rf:8,rs:1,a:1 |
| [4/5] | abbb | 8 | lf:8,rf:8,a:1 |
| [4/6] | baba | 5 | lf:5,rf:5,rp:1,a:3 |
| [5/0] | bbbab | 10 | lf:6,ls:4,rf:6,rs:4,a:1 |
| [5/1] | babbb | 10 | lf:8,lp:2,rf:8,rp:4,a:1 |
| [5/2] | ababb | 8 | lf:6,lp:2,rf:4,rp:1 |
| [5/3] | babba | 7 | lf:4,lp:1,ls:2,rf:1,rs:1 |
| [5/4] | abbba | 7 | lf:6,ls:1,rf:5,rs:1,a:1 |
| [5/5] | ababa | 7 | lf:5,lp:2,rf:3,rp:1,a:3 |
| [5/6] | babab | 4 | lf:4,rf:4,rp:1,a:3 |
| [6/0] | babbba | 9 | lf:6,lp:2,ls:1,rf:5,rp:3,rs:1,re:1,a:1 |
| [6/1] | abbbab | 6 | lf:4,ls:2,rf:4,rs:2,a:1 |
| [6/2] | ababbb | 6 | lf:5,lp:1,rf:4,rp:1,a:1 |
| [6/3] | ababab | 5 | lf:4,lp:1,rf:3,rp:1,a:3 |
| [6/4] | bbbbab | 4 | lf:2,ls:2,rf:2,rs:2,a:6 |
| [6/5] | baabba | 4 | lf:2,ls:2,rf:2,rs:2,a:6 |
| [6/6] | bbabba | 3 | lf:2,ls:1,rf:1,rs:1,a:1 |
| [7/0] | babbbab | 7 | lf:4,lp:1,ls:2,rf:4,rp:2,rs:2,lsrp:1,a:1 |
| [7/1] | abbbbab | 4 | lf:2,ls:2,rf:2,rs:2,a:6 |
| [7/2] | bbaabba | 4 | lf:2,ls:2,rf:1,rs:1,a:6 |
| [7/3] | ababbba | 4 | lf:3,lp:1,rf:2,rp:1,a:1 |
| [7/4] | aababbb | 3 | lf:2,lp:1,rf:1,rp:1,a:2 |
| [7/5] | abababa | 3 | lf:2,lp:1,rf:1,rp:1,a:3 |
| [7/6] | bbabbba | 2 | lf:1,ls:1,a:4 |
Considering [length 3 / frequency 1] bba=c.
Rewriting system is complete. See ⟨a, b | ababba=bab⟩.