| Back: | ⟨a, b | abaaba=aab⟩ |
|---|
Solved by morph:3/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaaba ⇒ aab |
| 2. | aababa ⇒ abaaab |
| 3. | aaabbaa ⇒ abaaaab |
| 4. | ababaaab ⇒ aabba |
| 5. | abaaabaab ⇒ aaabba |
| 6. | abaaaabba ⇒ aaabab |
| 7. | aabbaaba ⇒ aabab |
| 8. | aabbaaab ⇒ abaaabba |
| 9. | aabbabaaab ⇒ aababba |
| 10. | aabbaaaabba ⇒ aaabb |
| 11. | aababbaaba ⇒ abaaabb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 35 | lf:27,lp:7,ls:1,rf:19,rp:7,lprp:3 |
|---|---|---|---|
| [2/1] | ab | 33 | lf:25,lp:4,ls:4,rf:18,rp:4,rs:5,lsrp:1,lprs:2 |
| [2/2] | ba | 27 | lf:21,ls:6,rf:11,rs:4 |
| [2/3] | bb | 8 | lf:8,rf:6,rs:2,a:2 |
| [3/0] | aab | 27 | lf:17,lp:6,ls:4,rf:11,rp:4,rs:3,re:1,lprp:2,lsrp:2,lprs:1 |
| [3/1] | aba | 21 | lf:13,lp:4,ls:4,rf:7,rp:4,lsrp:2 |
| [3/2] | baa | 12 | lf:11,ls:1,rf:4 |
| [3/3] | bba | 10 | lf:8,ls:2,rf:4,rs:4,a:2 |
| [3/4] | aaa | 10 | lf:9,lp:1,rf:8,rp:3,a:1 |
| [3/5] | abb | 8 | lf:8,rf:6,rs:2,a:2 |
| [3/6] | bab | 4 | lf:4,rf:3,rs:2,a:1 |
| [4/0] | aabb | 11 | lf:7,lp:4,rf:5,rp:1,rs:2,lprs:1,a:2 |
| [4/1] | aaab | 11 | lf:7,lp:1,ls:3,rf:7,rp:3,rs:2,lprs:1,a:1 |
| [4/2] | aaba | 11 | lf:6,lp:2,ls:3,rf:3,rp:2,lsrp:1 |
| [4/3] | abba | 10 | lf:8,ls:2,rf:4,rs:4,a:2 |
| [4/4] | abaa | 9 | lf:6,lp:3,rf:4,rp:4 |
| [4/5] | bbaa | 6 | lf:5,ls:1,a:2 |
| [4/6] | baaa | 6 | lf:6,rf:4,a:1 |
| [5/0] | aabba | 13 | lf:7,lp:4,ls:2,rf:3,rp:1,rs:3,re:1,lprs:1,a:2 |
| [5/1] | baaab | 7 | lf:4,ls:3,rf:3,rs:1,a:1 |
| [5/2] | abbaa | 6 | lf:5,ls:1,a:2 |
| [5/3] | baaba | 6 | lf:3,ls:3 |
| [5/4] | abaaa | 6 | lf:4,lp:2,rf:4,rp:4,a:1 |
| [5/5] | aaabb | 4 | lf:3,lp:1,rf:4,rp:2,rs:2,re:1,a:4 |
| [5/6] | aabab | 4 | lf:2,lp:2,rf:3,rp:2,rs:2,re:1,a:1 |
| [6/0] | aabbaa | 8 | lf:4,lp:3,ls:1,a:2 |
| [6/1] | aaabba | 6 | lf:3,lp:1,ls:2,rf:2,rp:1,rs:2,re:1,a:4 |
| [6/2] | abaaab | 6 | lf:3,lp:1,ls:2,rf:3,rp:3,rs:1,re:1,a:1 |
| [6/3] | bbaaba | 4 | lf:2,ls:2,a:2 |
| [6/4] | aababb | 2 | lf:1,lp:1,rf:1,rp:1,a:8 |
| [6/5] | aabbab | 2 | lf:1,lp:1,a:10 |
| [6/6] | abbaab | 2 | lf:2,a:2 |
| [7/0] | abbaaba | 4 | lf:2,ls:2,a:2 |
| [7/1] | babaaab | 4 | lf:2,ls:2,a:3 |
| [7/2] | aaaabba | 4 | lf:2,ls:2,a:12 |
| [7/3] | aabbaaa | 4 | lf:2,lp:2,a:9 |
| [7/4] | aababba | 2 | lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:8 |
| [7/5] | aabbaab | 2 | lf:1,lp:1,a:2 |
| [7/6] | aabbaba | 2 | lf:1,lp:1,a:10 |
Considering [length 3 / frequency 1] aba=c.
Rewriting system is complete. See ⟨a, b | abaaba=aab⟩.