Morphocompletion for #1105 ⟨a, b | abaaab=aba

Solved by morph:4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaaab ⇒ aba
2. abaaaab ⇒ abaa
3. abaaaaab ⇒ abaaa
4. abaaaaaab ⇒ abaaaa
5. abaaaaaaab ⇒ abaaaaa
6. abaaaaaaaab ⇒ abaaaaaa
7. abaaaaaaaaab ⇒ abaaaaaaa
8. abaaaaaaaaaab ⇒ abaaaaaaaa
9. abaaaaaaaaaaab ⇒ abaaaaaaaaa
10. abaaaaaaaaaaaab ⇒ abaaaaaaaaaa
11. abaaaaaaaaaaaaab ⇒ abaaaaaaaaaaa
12. abaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaa
13. abaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaa
14. abaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaa
15. abaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaa
16. abaaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaa
17. abaaaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaaa
18. abaaaaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaaaa
19. abaaaaaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaaaaa
20. abaaaaaaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaaaaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] baa
Length 4:[4/0] aaaa, [4/1] abaa, [4/2] aaab, [4/3] baaa
Length 5:[5/0] aaaaa, [5/1] abaaa, [5/2] aaaab, [5/3] baaaa, [5/4] baaab
Length 6:[6/0] aaaaaa, [6/1] abaaaa, [6/2] aaaaab, [6/3] baaaaa, [6/4] baaaab
Length 7:[7/0] aaaaaaa, [7/1] abaaaaa, [7/2] aaaaaab, [7/3] baaaaaa, [7/4] baaaaab

Considering [length 4 / frequency 1] abaa=c.

Step 2

Rewriting system is complete. See a, b | abaaab=aba.