Morphocompletion for #1104 ⟨a, b | abaaab=aab

Solved by morph:4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaaab ⇒ aab
2. abaaaab ⇒ aaab
3. abaaaaab ⇒ aaaab
4. abaaaaaab ⇒ aaaaab
5. abaaaaaaab ⇒ aaaaaab
6. abaaaaaaaab ⇒ aaaaaaab
7. abaaaaaaaaab ⇒ aaaaaaaab
8. abaaaaaaaaaab ⇒ aaaaaaaaab
9. abaaaaaaaaaaab ⇒ aaaaaaaaaab
10. abaaaaaaaaaaaab ⇒ aaaaaaaaaaab
11. abaaaaaaaaaaaaab ⇒ aaaaaaaaaaaab
12. abaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaab
13. abaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaab
14. abaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaab
15. abaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaab
16. abaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaab
17. abaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaab
18. abaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaab
19. abaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaab
20. abaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aaa, [3/1] aab, [3/2] aba, [3/3] baa
Length 4:[4/0] aaaa, [4/1] aaab, [4/2] abaa, [4/3] baaa
Length 5:[5/0] aaaaa, [5/1] abaaa, [5/2] aaaab, [5/3] baaaa, [5/4] baaab
Length 6:[6/0] aaaaaa, [6/1] abaaaa, [6/2] aaaaab, [6/3] baaaaa, [6/4] baaaab
Length 7:[7/0] aaaaaaa, [7/1] abaaaaa, [7/2] aaaaaab, [7/3] baaaaaa, [7/4] baaaaab

Considering [length 4 / frequency 1] aaab=c.

Step 2

Rewriting system is complete. See a, b | abaaab=aab.