Morphocompletion for #1082 ⟨a, b | aabbaa=aab⟩

Back:⟨a, b | aabbaa=aab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaa ⇒ aab
2. aabbbaa ⇒ aabb
3. aababbaa ⇒ aabab
4. aabbbbaa ⇒ aabbb
5. aababbbaa ⇒ aababb
6. aabbabbaa ⇒ aabbab
7. aabbbbbaa ⇒ aabbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] baa, [3/1] aab, [3/2] bba, [3/3] abb, [3/4] bbb, [3/5] bab, [3/6] aba
Length 4:[4/0] bbaa, [4/1] aabb, [4/2] bbba, [4/3] abbb, [4/4] abba, [4/5] aaba, [4/6] bbbb
Length 5:[5/0] bbbaa, [5/1] abbaa, [5/2] aabbb, [5/3] aabba, [5/4] aabab, [5/5] bbbba, [5/6] babba
Length 6:[6/0] bbbbaa, [6/1] babbaa, [6/2] abbbaa, [6/3] aabbbb, [6/4] aababb, [6/5] aabbba, [6/6] aabbab
Length 7:[7/0] bbbbbaa, [7/1] bbabbaa, [7/2] babbbaa, [7/3] abbbbaa, [7/4] ababbaa, [7/5] aabbbbb, [7/6] aabbbba

Considering [length 4 / frequency 0] bbaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbaa=aab⟩.