Morphocompletion for #1073 ⟨a, b | aababa=baa

Solved by morph:3/1,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababa ⇒ baa
2. aababbaa ⇒ babaa
3. aababbbaa ⇒ babbaa
4. aababbabaa ⇒ bababaa
5. aababbbbaa ⇒ babbbaa
6. aababbabbaa ⇒ bababbaa
7. aababbbabaa ⇒ babbabaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] bab
Length 4:[4/0] aaba, [4/1] bbaa, [4/2] babb, [4/3] abab
Length 5:[5/0] aabab, [5/1] ababb, [5/2] bbbaa, [5/3] babba
Length 6:[6/0] aababb, [6/1] bbabaa, [6/2] babbaa, [6/3] ababbb

Considering [length 3 / frequency 1] baa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ c
2. cbac ⇒ bca
3. aabac ⇒ ca
4. aacabac ⇒ caa
5. bcaa ⇒ ccabac
6. baca ⇒ cabac
7. cbaba ⇒ bc
8. aababa ⇒ c
9. cababa ⇒ bac
10. aababc ⇒ bac
11. ccababc ⇒ bcc
12. aacababc ⇒ cc
13. cacababc ⇒ bacc
14. bbac ⇒ cbabc
15. babac ⇒ cababc
16. bcabac ⇒ cbabca
17. aababbc ⇒ babc
18. ccababbc ⇒ bcbc
19. aacababbc ⇒ cbc
20. bbabc ⇒ cbabbc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] bc, [2/3] aa, [2/4] ac, [2/5] ca, [2/6] bb
Length 3:[3/0] aba, [3/1] bac, [3/2] bab, [3/3] abc, [3/4] cab, [3/5] aab, [3/6] bbc
Length 4:[4/0] babc, [4/1] abab, [4/2] caba, [4/3] baba, [4/4] abac, [4/5] aaba, [4/6] abbc
Length 5:[5/0] ababc, [5/1] cabab, [5/2] babbc, [5/3] aabab, [5/4] aacab, [5/5] ababa, [5/6] cabac

Considering [length 3 / frequency 0] aba=d.

Step 3

Rewriting system is complete. See a, b | aababa=baa.