Morphocompletion for #1053 ⟨a, b | aaabba=baa⟩

Solved by morph:2/1,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabba ⇒ baa
2. aaabbbaa ⇒ babaa
3. aaabbbbaa ⇒ babbaa
4. aaabbbabaa ⇒ bababaa
5. aaabbbbbaa ⇒ babbbaa
6. aaabbbabbaa ⇒ bababbaa
7. aaabbbbabaa ⇒ babbabaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa33lf:20,lp:7,ls:6,rf:7,rs:7,lprs:7,lsrs:6
[2/1]bb18lf:18,rf:5
[2/2]ba11lf:10,ls:1,rf:16,rp:7,lsrp:1
[2/3]ab10lf:10,rf:9
[3/0]aaa14lf:7,lp:7
[3/1]baa12lf:6,ls:6,rf:7,rp:1,rs:7,re:1,lsrs:6
[3/2]bbb10lf:10,rf:1,a:1
[3/3]bba9lf:8,ls:1,rf:4
[4/0]aaab14lf:7,lp:7
[4/1]bbaa8lf:4,ls:4,rf:3,rs:3,lsrs:3,a:1
[4/2]aabb7lf:7
[4/3]bbba6lf:6,rf:1,a:1
[5/0]aaabb14lf:7,lp:7
[5/1]bbbaa6lf:3,ls:3,rf:1,rs:1,lsrs:1,a:1
[5/2]aabbb6lf:6,a:1
[5/3]babaa4lf:2,ls:2,rf:3,rp:1,rs:3,re:1,lsrs:2,a:1
[6/0]aaabbb12lf:6,lp:6,a:1
[6/1]bbbbaa4lf:2,ls:2,a:3
[6/2]bbabaa4lf:2,ls:2,rf:1,rs:1,lsrs:1,a:2
[6/3]aabbbb3lf:3,a:3

Considering [length 2 / frequency 1] bb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ aaaca
2. aaacaaca ⇒ caa
3. bcaa ⇒ caaaca
4. bacaa ⇒ aaaccaa
5. cb ⇒ bc
6. bb ⇒ c
7. aaacaaccaa ⇒ cacaa
8. bccaa ⇒ ccaaaca
9. baccaa ⇒ aaacccaa
10. bcacaa ⇒ caaaccaa
11. bacacaa ⇒ aaaccacaa
12. aaacaacccaa ⇒ caccaa
13. bcccaa ⇒ cccaaaca
14. bacccaa ⇒ aaaccccaa
15. bcaccaa ⇒ caaacccaa
16. bacaccaa ⇒ aaaccaccaa
17. bccacaa ⇒ ccaaaccaa
18. baccacaa ⇒ aaacccacaa
19. bcacacaa ⇒ caaaccacaa
20. bccccaa ⇒ ccccaaaca
...

Collecting factors up to length 6 / frequency 7:

[2/0]aa46lf:26,lp:3,ls:17,rf:43,rp:7,rs:13,lsrp:7,lprs:3,lsrs:12,a:2
[2/1]ca29lf:28,ls:1,rf:32,rp:7,rs:5,lsrp:1,a:2
[2/2]ac20lf:20,rf:21,a:2
[2/3]bc16lf:8,lp:8,rf:1,rp:1,rs:1,re:1,a:3
[2/4]cc16lf:16,rf:24,rp:4,a:6
[2/5]ba14lf:7,lp:7,a:2
[3/0]caa35lf:19,ls:16,rf:21,rp:5,rs:13,re:1,lsrp:4,lsrs:12,a:4
[3/1]aca14lf:13,ls:1,rf:9,rs:5,a:2
[3/2]bac12lf:6,lp:6,a:7
[3/3]cca11lf:11,rf:16,rp:2,a:6
[3/4]bcc8lf:4,lp:4,a:6
[3/5]bca8lf:4,lp:4,a:5
[3/6]cac8lf:8,rf:6,rp:2,a:8
[4/0]ccaa18lf:9,ls:9,rf:12,rp:2,rs:8,lsrp:1,lsrs:5,a:6
[4/1]acaa15lf:9,ls:6,rf:4,rs:4,lsrs:3,a:4
[4/2]bcac6lf:3,lp:3,a:9
[4/3]bacc6lf:3,lp:3,a:10
[4/4]baca6lf:3,lp:3,a:7
[4/5]caca6lf:6,rf:4,rp:1,a:8
[4/6]aaac6lf:3,lp:3,rf:15,rp:7,a:2
[5/0]cacaa10lf:5,ls:5,rf:4,rp:1,rs:4,re:1,lsrs:3,a:8
[5/1]cccaa8lf:4,ls:4,rf:5,rp:1,rs:3,lsrp:1,lsrs:1,a:10
[5/2]accaa8lf:4,ls:4,rf:5,rs:5,lsrs:1,a:7
[5/3]aaaca6lf:3,lp:3,rf:5,rp:1,rs:5,re:1,a:2
[5/4]bcaca4lf:2,lp:2,a:9
[5/5]bacca4lf:2,lp:2,a:10
[5/6]bacac4lf:2,lp:2,a:11

Considering [length 3 / frequency 0] caa=d.

Step 3

Rewriting system is complete. See ⟨a, b | aaabba=baa⟩.